Find substructures within groups and partition elements into equal-size cosets
Inside most groups live smaller groups. Shift copies of one around and they tile the whole group in equal pieces.
Choose a group and a subgroup, and watch its elements light up on the Cayley diagram.
|H| = 1, |G| = 6, index = 6
Within every group live smaller groups -- subgroups. The rotations inside a dihedral group form a subgroup. The even permutations inside S_n form the alternating group A_n. Subgroups partition the group into equal-size pieces called cosets, leading to Lagrange's beautiful theorem.
Select a subgroup and watch it light up on the Cayley diagram. Notice how subgroup elements cluster together.
Key insight: A subgroup is a subset that is itself a group under the same operation. It must contain the identity, be closed under multiplication, and contain all inverses.
Choose a group and a subgroup to color each of its cosets. Every element gets exactly one color, and every color covers the same number of elements.
All cosets have equal size (1). Normal subgroup.
Color each coset a different color on the Cayley diagram. The cosets form a perfect partition -- every element belongs to exactly one coset, and all cosets have the same size.
Key insight: Left cosets gH = { gh : h in H }. They partition G into |G|/|H| pieces, each of size |H|. This is why subgroup order always divides group order.
Choose a group and compare each subgroup's order with the group's order. Every subgroup order divides it.
Lagrange's Theorem: The order of every subgroup divides the order of the group.
| Subgroup | |H| | |G| | |G|/|H| | Divides? |
|---|---|---|---|---|
| H0 | 1 | 6 | 6 | Yes |
| H1 | 2 | 6 | 3 | Yes |
| H2 | 2 | 6 | 3 | Yes |
| H3 | 2 | 6 | 3 | Yes |
| H4 | 3 | 6 | 2 | Yes |
| H5 | 6 | 6 | 1 | Yes |
Subgroup orders as fractions of |G| = 6:
For any finite group G and subgroup H, |H| divides |G|. Explore different groups and see that every subgroup order is a divisor of the group order.
Key insight: Lagrange's theorem is a powerful constraint. A group of order 12 can only have subgroups of order 1, 2, 3, 4, 6, or 12. The converse is false: not every divisor need correspond to a subgroup.
Spot a mistake or have an idea?